Question

in the given figure, p is a point equidistant from two lines l and m intersecting at point A. prove that ∆ABP and ∆ACP are congruent and length of AC is 8cm.​

Answer 1

Answer:

Pc=pb

Ap is common

< apc=<abp

Step-by-step explanation:

Hence proved triangle is congruent

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Answer 2

Step-by-step explanation:

in

triangle ABP and ACP

PROOF:

ANGLE B =ANGLE C (90 DEGREE)

AP=AP(COMMON SIDE)

TRIANGLE ABP=TRIANGLE ACP(BY SAS POSTULATE)