Question

In the given figure P is a point on the side BC of triangle ABC prove that AB + BC + AC greater than 2AP

Answer 1

Step-by-step explanation:

In triangle ABP,

(Sum of any two sides is greater than 3rd side)

AB+BP>AP - 1.

Similarly, in triangle ACP,

(Sum of any two sides is greater than 3rd side)

AC+CP>AP - 2

By adding 1 and 2 We have,

AB+BP+AC+CP>AP+AP

AB+BC+AC>2AP. ( Since, BP+CP=BC )