Question

In the given figure , PA and PB are the two tangents to a circle at A and B respectively if O is centre of circle and < AOB = 140 , find < APB = 40

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

The value of ∠APB=40°

Step-by-step explanation:

Given PA and PB are the two tangents to a circle at A and B respectively. If O is the center of circle and ∠AOB is 140°

we have to find the angle ∠APB.

As we know radius of circle perpendicularly bisect the tangent of that circle.

As the sum of all angles of quadrilateral is 360

∴ ∠1+∠2+x+140°=360°

⇒ 90°+90°+x+140°=360°

⇒ 320°+x=360°

⇒ x=40°

Hence, ∠APB=40°