Question

In the given figure PA and PB are two tangents from an external point P to a circle with centre O if PBA=65 degree find angle OAB ​

Answer 1

Answer:

angle OAB = 25 degree

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Answer 2

Answer:

25°

Step-by-step explanation:

Here, PA = PB (tangents drawn from an external point to a circle are equal)

Therefore, angle PBA = angle PAB = 65°

Also, OB = OA, hence angle OBA = angle OAB

Now, OB is perpendicular to PB (radius is perpendicular to tangent)

therefore, angle PBA + angle OBA = 90°

=> 65 + OBA = 90

=> OBA = 25°

=> OAB = 25° (since, OAB = OBA)

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