In the given figure parallelogram ABCD and ∆BCP are on the same base BC and between the same parallels. If ar
(BCP) - 15 cm', then ar (ABCD) is equal to
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area of triangle with same base and between same parallel is half of the area of parallelogram
so area is 30 cm^2
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5
if a triangle and a parallelogram lie on the same. base and between same parallel lines then
area of parallelogram=2(area of triangle)
area of (ABCD)=2×15
30
hope it helps you dude
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