Question

in the given figure, POQ in a line . ray OR is perpendicular to line PQ.OS is another ray lying between Ray's OPandOR
prove that angle ROS = 1/2 ( QOS _ POS)​

Answer 1

Answer:

/* From the figure ,

\angle ROS = \angle QOS - \angle QOR \:---(1)

\angle ROS = \angle ROP - \angle POS \:---(2)

/* Adding (1) and (2)

\angle ROS + \angle ROS = \angle QOS - \angle QOR + \angle ROP - \angle POS

Since , \angle QOR = \angle ROP = 90\degree \:(given)

\implies 2\angle ROS = \angle QOS - \angle POS

\implies \angle ROS = \frac{1}{2} [\angle QOS - \angle POS ]

Step-by-step explanation:

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