Question

in the given figure, PQ=CB, PA=CR, Angle P= angle C Prove that ∆QRP congruent ∆BCA​

Answer 1

Answer:

here when PA=CR then the two sides are equal and when,PQ=CB then these two sides are equal so triangle QPR is congurent to traingle BCA

Answer 2

PQ=CB(given)
PA=CR(given)
Angle P=Angle C(given)
Point A and Point R are common
So bySAS congruence criteria triangle QPR AND triangle BCA are congruent