in the given figure PQ is a chord. the length of OT is 6cm and the radius of the circle is 3cm. TP and TQ are the two tangents drawn from an external point T.find angle PTQ
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here is your answer.........
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sabarikarthick:
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Here,∠PTO=∠QTO=a (∵ The line Joining the point and centre bisects the angle between the Tangent from that point)
Applying Sin in triangle OTP we get
Sina=3/6=1/2=Sin(30°)
So,a=30°
So, ∠PTQ=60°
Applying Sin in triangle OTP we get
Sina=3/6=1/2=Sin(30°)
So,a=30°
So, ∠PTQ=60°
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