Question

In the given figure PQ is perpendicular to AB, AQ =QB, angle PAC =42° angle c =68° Find angle ABC


Please answer it!​

Answer 1

Answer:

∠ABC = 35°

Step-by-step explanation:

Let ∠ABC be x

For ΔAQP and ΔBQP

    ∠AQP = ∠BQP

    AQ = BQ and

    QP is common side

∴  ΔAQP ≅ ΔBQP

So, ∠QAP = ∠QBP = x

As sum of interior angles of any triangle is 180°.

∠ABC + ∠BCA + ∠CAB = 180°

⇒ x + (x + 42°) + 68° = 180°

⇒ 2x + 110° = 180°

⇒ 2x = 70°

⇒ x = 35°