Question

in the given figure PQ PR and a b are tangents at point Q R and S respectively of a circle if PQ equal to 8 cm find the perimeter of triangle APB

Answer 1

Per(∆PAB)=PA+PB+AB
AS=QA(Tangents from A)(1)
BS=BR(Tangents from B)(2)

PA+PB+AS+BS(3)
From ()1(2)(3)
Pa+aq+pb+br
Pq+pr
2pq



Pq=1/2 per(∆pab)
Per=2*8=16 cm

Answer 2

The perimeter of Δ APB = 16 cm

Step-by-step explanation:

Given that PQ , PR and a , b are tangents at point Q , R and S and PQ = 8 cm

To find : Perimeter of Δ APB

If AQ = AS

Therefore, BR = BS

If,  PQ = PR

then PQ = PR = 8 cm

Now,   AP = PQ - AQ

           AB = AS + BS

           PB = PR - BR

Perimeter of ΔAPB = AP + PB + AB

    Put all sides  in perimeter

ΔAPB = PQ - AQ + PR - BR + AS + BS  

          = PQ + PR - AS - BS + AS + BS  [we already know AQ = AS , BR = BS]

          = PQ + PR

         = 8 + 8

        =  16 cm

Hence, the perimeter of Δ APB = 16 cm