Question

In the given figure PQRS is a square lawn with sides PQ = 42 m. Two circular flower beds are there on the sides PS and PQ with the CENTRE O, the intersection of its diagonals. Find the total area of the two flower beds.

Answer 1

Answer:

1386 m².

Step-by-step explanation:

In the figure as we are shown,

There are two semi-circles at PS and QR.

The length of the side, PQ = 42 m.

PQRS is a square.

Therefore, the Total Area of the two flower beds are given by,

Area of circle having diameter = 42 m

So,

$Area\,of\,circle=\pi r^{2}$

As,

Diameter, D = 42 m

Radius, r = D/2 = 21 m

So,

Area of circle is,

$\pi r^{2}=\frac{22}{7}(21)^{2}=22\times 21\times 3=1386\,m^{2}$

Therefore, the area of two flower beds is 1386 m².

Answer 2

1386 cm2 is the area of shaded region