Question

in the given figure, prove that BF||DE​

Answer 1

We, know that sum of angles in a ∆ is 180°

So, ∠A + ∠B + ∠C = 180°

→ 65° + ∠B + 55° = 180°

→ ∠B = 180° - 55° - 65°

→ ∠B = ∠ABC = 60°

Now, ∠CBF + ∠ABC = 180°

So, ∠CBF = 180° - 60° = 120°

Here, ∠CBF = ∠BDE = 120°

HENCE, BF || DE (Proved)

Answer 2

Answer:

Step-by-step explanation:

Refer to the attachment below.