In the given figure PS=QR and angleSPQ=angleRQP.Prove that PR=QS and angleQPR=anglePQS
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Hey there !
In triangles QPR and PQS ,
PQ = PQ [ Common ]
∠RQP = ∠SPQ [ Given ]
PS = QR [ Given ]
ΔQPR ≅ ΔPQS [ SAS ]
PR = QS [ CPCT ]
∠QPR = ∠PQS [ CPCT ]
HOPE THIS HELPS...
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