In the given figure pt. O is thr centre of the circle. Angle AOC is 135degree. Find arc BC and angle BPC
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Given : O is the centre of the circle.
∠AOC = 135°
To Find : arc BC and ∠BPC
Solution:
AOB is straight line
Hence ∠AOC + ∠BOC = 180°
=> 135° + ∠BOC = 180°
=> ∠BOC = 45°
arc BC = 45°
∠BOC = 2 ∠BPC ( angle by same arc BC at center and remaining circle)
=> 2 ∠BPC = 45°
=> ∠BPC = 22.5°
arc BC = 45°
∠BPC = 22.5°
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