Question

~In the given figure, QA perpendicular to AB and PB perpendicular to AB. If AO=20 cm, BO=12 cm, PB=18 cm find AQ.

Answer 1

Solution:-
Given QA ⊥ AB and PB ⊥ AB so,
∠ QAO = ∠ PBO = 90° ...... (1)
In Δ AOQ and Δ BOP
∠ QAO = ∠ PBO  (from equation 1)
∠ AOQ = ∠ BOP .. (vertically opposite angles)
So,
Δ AOQ is same as Δ BOP .. (by AA rule)
Then we get:
⇒ OAAQ = OBBP
⇒ 20AQ = 1218
⇒ AQ = 20 × 1812
⇒ AQ = 5 × 183 
⇒ AQ = 5 × 6 = 30 cm


 

Answer 2

Answer:

Step-by-step explanation: