In the given figure QP //RS Angle PQR =30 , angle QTS =50 . find angle TQR give reason
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Answered by
11
Hey!!!!
Here PQ II RS
=> PQ II TS
and TQ is a transversal
Then
angle PQT = angle QTS
=> angle PQR + x = 50°
=> 30 + x = 50
Thus x = 20°
Hope this helps
Here PQ II RS
=> PQ II TS
and TQ is a transversal
Then
angle PQT = angle QTS
=> angle PQR + x = 50°
=> 30 + x = 50
Thus x = 20°
Hope this helps
Answered by
13
Hey...!!!
OP || RS
And, QT is transversal line.
So, Angle PQT = Angle STQ (alternate angle)
So,
30 + x = 50
X = 50 - 30
X = 20°
So, Angle TQR = 20°
Hope it helps...!!!
OP || RS
And, QT is transversal line.
So, Angle PQT = Angle STQ (alternate angle)
So,
30 + x = 50
X = 50 - 30
X = 20°
So, Angle TQR = 20°
Hope it helps...!!!
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