Question

IN THE GIVEN FIGURE,R1=6 OHM,R2=2 OHM AND R3=4 OHM.FIND THE CURRENT.(GIVEN,VOLTAGE = 6V)​

Answer 1

Explanation:

total resistance = R1+R2+R3. ( series connection)

R = 2++6+4

R = 12 ohm

V = IR

6 =I 12

I = 6/12

I = 1/2A or 0.5A

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Answer 2

Answer:2 A

Explanation:4Ω and 2Ω are in series.∴R₁ + R₂ = 6Ω=Rs

Both 6Ω and 6Ω are in parallel.∴Rp = 3Ω

∴Effective Resistance =  3Ω

∴I = 6V/3Ω = 2A.