Question

In the given figure, rays OA,OB,OC and OD are such that angle AOB= 56° angle BOC=100°,angle COD=x° and angle DOA = 74° find the value of x
sum of all the angles around a point is 360°.......

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Answer 1

Answer:

hope it will help you

Step-by-step explanation:

Let angle COD be x

x+100*+56*+74*=360*(by A.S.P.T)

x+220*=360*

x=360*-220*

x=140*

Hence,

angle COD=140*