In the given figure, rays OA, OB, OC, OD and OE are such that ∠AOB=47 °, ∠BOC=X °, [2] ∠COD=83 °, ∠DOE= 92 ° and ∠EOA=75 °. Find the value of x
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Answer:
let angle COD be x
x+100*+56*+74*=360*(by A.S.P.T)
x+220*=360*
x=360*-220*
x=140*
Hence,
angle COD=140*
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solution
solutionLet angle COD be x
solutionLet angle COD be xx+100*+56*+74*=360*(by A.S.P.T)
solutionLet angle COD be xx+100*+56*+74*=360*(by A.S.P.T)x+220*=360*
solutionLet angle COD be xx+100*+56*+74*=360*(by A.S.P.T)x+220*=360*x=360*-220*
solutionLet angle COD be xx+100*+56*+74*=360*(by A.S.P.T)x+220*=360*x=360*-220*x=140*
solutionLet angle COD be xx+100*+56*+74*=360*(by A.S.P.T)x+220*=360*x=360*-220*x=140*Hence,
solutionLet angle COD be xx+100*+56*+74*=360*(by A.S.P.T)x+220*=360*x=360*-220*x=140*Hence,angle COD=140*
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