In the given figure, RQ is tangent with centre at O. If SQ = 8 cm, QR = 3 cm find OR
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Step-by-step explanation:
sq=6cm = oq=3cm
qr=4cm , since rq is a tangent to the circle at q
angle rqo=90 {tangent is perpendicular to the radius of a circle
in triangle rqo, {pythagores theorem}
or^2 = qr^2 + oq^2
or^2 = 4^2 + 3^2
or^2 = 25
or = 5cm
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