In the given figure, RQST is a quadrilateral and PQS PRT. Show that PQR ~ PTS.
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In △TPS and △TRQ
∠PST=∠RQT
∠SPQ=∠QRT
[∵ exterior angle of cyclic quadrilateral is equal to the interior opposite angle]
∠T=∠T (common)
∴△TPS−△TRQ (By AA)
Step-by-step explanation:
hope you have been understood
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