In the given figure s is a point on the side QR of pqr prove that PQ +QR+PR+2PS
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Step-by-step explanation:
As we know that the sum of two sides is always greater than the third side. in triangle pqs, pq+qs>ps and in triangle psr, pr+sr>ps adding the above two equations, we get pq+pr+rq>2ps hence,proved.
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