Question

In the given figure, show that
(i) EF | AB
(ii) AB II CD
(iii) EF || CD
Justify your answer.
​

Answer 1

Answer:

since,

√ DCB = 70° = √ (FBC + ABF), so these

make alternate interior angle.

so ,AB || CD

now,

√ ABF + √ BFE = 35° + 145° = 180° ( Adjacent Angel)

So, EF || AB

And,

Because AB is parallel to both EF and CD

So, EF || CD

hence proved...

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Answer 2

Answer:

since,

DCB = 70° =  (FBC + ABF), so these

make alternate interior angle.

so ,AB || CD

now,

ABF +  BFE = 35° + 145° = 180° ( Adjacent Angel)

So, EF || AB

And,

Because AB is parallel to both EF and CD

So, EF || CD

hence proved...