Math, asked by meenumalik198, 2 months ago

In the given figure, show that
(i) EF | AB
(ii) AB II CD
(iii) EF || CD
Justify your answer.

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Answers

Answered by fizam648
9

Answer:

since,

DCB = 70° = (FBC + ABF), so these

make alternate interior angle.

so ,AB || CD

now,

ABF + BFE = 35° + 145° = 180° ( Adjacent Angel)

So, EF || AB

And,

Because AB is parallel to both EF and CD

So, EF || CD

hence proved...

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Answered by arpitakhare2007
0

Answer:

since,

DCB = 70° =  (FBC + ABF), so these

make alternate interior angle.

so ,AB || CD

now,

ABF +  BFE = 35° + 145° = 180° ( Adjacent Angel)

So, EF || AB

And,

Because AB is parallel to both EF and CD

So, EF || CD

hence proved...

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