Question

write 4x-5x²+6=0 in standard form
of quadratic equation.​

Answer 1

Answer:

x = $\frac{2}{5}$ + $\frac{-1}{5}$$\sqrt{34}$ or x = $\frac{2}{5}$  + $\frac{1}{5}$$\sqrt{34}$

Step-by-step explanation:

Let's solve  your equation step by step

4x-5x²+6=0

Step 1: Simplify both side of the equation.

-5$x^{2}$ + 4x + 6 = 0

For this equation: a=-5, b=4, c=6

-5$x^{2}$ + 4x + 6 = 0

Step 2: Use quadratic formula with a=-5, b=4, c=6.

x = $\frac{-b + \sqrt{b^{2} - 4ac}}{2a}$

x = $\frac{-(4) + \sqrt{(4)^{2} -4(-5)(6) } }{2(-5)}$

x = $\frac{-4 + \sqrt{136} }{-10}$

x = $\frac{2}{5}$ + $\frac{-1}{5}$$\sqrt{34}$ or x = $\frac{2}{5}$  + $\frac{1}{5}$$\sqrt{34}$

Answer:

x = $\frac{2}{5}$ + $\frac{-1}{5}$$\sqrt{34}$ or x = $\frac{2}{5}$  + $\frac{1}{5}$$\sqrt{34}$

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