Question

in the given figure sides QP and RQ andΔPQR are produced to points S and T respectivly.
If triangle SPQ =135° and triangle PQT=110°,find trianglePRQ.

plz say with explaintion ​

Answer 1

Answer:

Given:-

∠SPQ =135° and triangle PQT=110°

To Find:-

• triangle PRQ.

$\sf \: ∠PQT+∠PQR=180°$

(Straight angle made on line TR at point Q)

$\sf \: 110 {}^{0} +∠PQR=180 {}^{0}$

∠PQR=180° −110° =70°

$\sf \pink{In \: \: △ \: PQR}$

∠PSR=∠PQR+∠PRQ (Exterior angle of triangle is equal to sum of two interior angles)

$\sf \: 135 {}^{0} =70 {}^{0} +∠PRQ$

$\sf \: ∠PRQ=135 {}^{0} −70 {}^{0} =65 {}^{0}$

Hence, This is Answer