Question

In the given figure, sides QP and RQ of ∆PQR are produced to points S and T respectively. If SPR = 135º and PQT = 110º, find PRQ.

Answer 1

here this answer

$spr = pqr + prq \: and \\ pqt = qpr + prq \\ pqr + prq = 135 \\ qpr + prq = 110 \\ pqr + prq + qpr + prq = 135 + 110 \\ 180 + prq = 245 \\ prq = 245 - 180 \\ prq = 65$
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Answer 2

Hi dear here is your answer.