Math, asked by mili2007, 3 months ago

In the given figure, the area enclosed
between the concentric circles is 770 cm²
If the radius of the outer circle is
21cm, calculate the area of the inner
circle.​

Answers

Answered by sainiinswag
0

Answer:

figure is missing... plz provide figure

Answered by gurvanshdeep1234
1

Answer:

Let the radius of the inner circle be r cm. Then,

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770π(441−r

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770π(441−r 2

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770π(441−r 2 )=770

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770π(441−r 2 )=7707

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770π(441−r 2 )=770722

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770π(441−r 2 )=770722 ×(441−r

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770π(441−r 2 )=770722 ×(441−r 2

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770π(441−r 2 )=770722 ×(441−r 2 )=770r 2

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770π(441−r 2 )=770722 ×(441−r 2 )=770r 2 =196

Let the radius of the inner circle be r cm. Then,(π×21×21)−πr 2 =770π(441−r 2 )=770722 ×(441−r 2 )=770r 2 =196r=14 cm

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