Question

In the given figure the bisectors of angle ABC and angle BCA , intersect each other at point O . If angle BOC = 100° , the angle A is(a) 30° (b) 20°(c) 40° (d) 50°

Answer 1

as it is given that angle abc the bisector of angle abc is the line segment ab and the bisector of angle ACB and it is given that is hundred degrees b + BC + AC is equal to 180 according to angle sum property 200 degree + angle abc + OC b is equal to 180 degree as OBC is equal to ocv than hundred degree + 2 angle abc is equal to 180 degree and hence OBC is equal to 40 degree of OBC is 40 degrees in ACB is also 40 degree and a b c is equal to a + OBC as OBC is equal to AV hands ABC is equal to 80 degree that is equal to AC then 80 degree + 80 degree angle a is equal to 180 degree that is 160 degree + angle a is equal to 180 degree angle is equal to 180 degree minus 160 degree that is equal to angle a is equal to 20 degree