in the given figure the length of arcs a b and b c are in the ratio 3 is to 2 if angle aob is 96 degree find angle BOC and angle abc
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Step-by-step explanation:
OAB and OBC are isosceles triangle
Let angle oab=abo=x
Let angle obc=bco=y
2x+96=180
x=42
ab/bc=3/2
2ab=3bc
2x96*2πr/360=3xα*2πr/360
(where α=angle boc)
2*96=α*3
α=64
in triangle boc,
2y+64=180
y=58
x+y=42+58=110
And hence,
angle boc=64
angle abc=110
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