Question

In the given figure, the point Pbisects AB and DC. Prove that ∆APC = ∆BPD​

Answer 1

Answer:

given figure P bisect AB and DC

Then P is the mid point of AB and CD

Then AP=PB

And CP=PD

Then in ΔAPC and ΔBPD

AP=PB

CP=PD

∠APC=∠BPD...(vertically opposite angles)

∴ΔAPC≅ΔBPD

Step-by-step explanation:

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