In the given figure the side of the square is 10 cm. EF=2.5 cm and c and D are halfway between the top and bottom sides of the figure. What is the area of the shaded portion?
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Answer:
We know that area of rectangle = length x
breadth
& area of trapezium 1 2 X
sum of parallel sides height.
From the given figure, we have
AB = 10cm
CD= EF = 2.5cm
EC FD = 5cm
Trapezium ABCD has height = 10 − 5 = 5cm
Area of the shaded part = Area of rectangle CEF D+ Area of trapezium ABCD
1 = 2.5 × 5 + = x (2.5 +10) × 5 = 12.5+ 31.25 = 2
43.75cm²
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