Question

Root 23+xroot10= root18 +root 5
$\sqrt{23 + x \sqrt{10} } = \sqrt{18 } + \sqrt{5 }$

Answer 1

Given Equation is $\sqrt{23 + x \sqrt{10}} = \sqrt{18} + \sqrt{5}$

On Squaring both sides, we get

= > ($\sqrt{23 + x \sqrt{10}$)^2 = ($(3 \sqrt{2} + \sqrt{5} )^2$


We know that (a+b)^2 = a^2+b^2+2ab.


= > ($23 + x \sqrt{10}$ = $(3 \sqrt{2})^2 + 2 * 3 \sqrt{2} * \sqrt{5} + ( \sqrt{5})^2$


= > 23+x$\sqrt{10} = 6 \sqrt{10} + 23$


= > x$\sqrt{10} = 6 \sqrt{10}$


=> x = 6.


Hope this helps!

Answer 2

answer

x=6

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