Question

if sec +tan + 1= 0 find the sec - tan

Answer 1

Seca-tana=-1
It's your answer
First we use
Sec^2a-tan^2a=1
Then solve by using eq.
Thanks

Answer 2

Given Equation is sec theta + tan theta + 1 = 0

It can be written as sec theta + tan theta = -1 -------------- (1).

We know that $sec^{2}theta$ - $tan^{2}theta$ = 1

            = (sec theta + tan theta)(sec theta - tan theta) = 1   (a^2-b^2 = (a+b)(a-b))

            = (-1)(sec theta - tan theta) = 1

            = sec theta - tan theta = -1.


Hope this helps!