Question

in the given figure , the sides AB and AC of triangle ABC are produced to points E and D respectively .
if bisectorsCBE and CO of angle CBE and angle BCD respectively meet at the point O , then prove that angle BOC = 90° - 1/2 (angle BAC).


plz help me guys....​

Answer 1

this is your answer.......

Answer 2

Answer:

ur answer is attached above mate