in the given figure the sides PQ and PR are produced toS and R respectively and ANGLE SQR is greater than angleTRQ .provethat PR is smaller than PQ
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Use the theorem angle opposite to greater side is greater..... First take the linear pair and do the opposite... I mean the angle which is already given that it is bigger u will come to know that the linear pair of it will be smaller it means the side will also be smaller..... Just go through this procedure.
Tagguasha:
SORRY!! i can't understand it.
Answered by
17
Hi, ∠SQR<∠TRQso 180−∠SQR>180−∠TRQor ∠TQR>∠PRQhence PR>PQas side oppsoite to greater angle is greater NOTE:you may have thinking how 180−∠SQR>180−∠TRQso take an example, 2<5but 10−2>10−5same concept is used here
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