Question

In the given figure , triangle ABC and DCB are right - angled at A and D respectively and AC = DB. Prove that triangle ABC is congruent to triangle DCB.​ who will ans first i will mark him or her as brainlist plz ans fast my one chapter is pending

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$In \: \triangle ABC \: and \: \triangle \: DCB \\ \angle BAC \cong \angle CDB \: .....(each \: 90 \degree) \\ hyp BC \cong hyp BC .....(common \: side) \\ side AC \cong side DB .....(given) \\ \therefore \: by \: right - hypotenuese - side \: \\ (rhs) \: criterion \:of \: congruence \\ \triangle ABC \cong \triangle \: DCB$