in the given figure triangle ABC is congruent to triangle ETA if x and y are points lying on it and easy respectively such that a x by x is equal to e y y y is equal to 1 value of DX by f y is always
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equal to one I think this is the ryt ans.
senthil83:
please solve the steps
its clear tht if the triangles are equal than every thing lying on it are too equal ...though its clear for defining
well is my ans. correct
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<EGF = <DGC = 90° - <C
<E = <A = 90° - <C
<E = <EGF = >EF = FG
FY is the median in the triangle FEG
FY is the perpendicular to ED
FE // AC (this is the equation 1)
Join BX
BX is the median of triangle ABC
BX = 1/2 AC = XC
<XBC = <C = DAE
ABFX is cyclic quadrilateral
<<AXF = 180° - <ABF = 90°
FX is perpendicular to AC (this equation will be 2)
so from equation 1 and 2
DXFY is a rectangle = DX = FY
DX/FY = 1
If there is any confusion please leave a comment below.
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