in the given figure triangle ABC is right angled at A. semicircle are drawn on AB, AC and BC as diameters. It is given that AB=3 cm and AC= 4 cm. find area of shaded region.
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area of shaded region = area of semicircle AB +
area of semicircle AC - (area of semicircle on side BC+area of triangle ABC)=6SQ UNITS
area of semicircle AC - (area of semicircle on side BC+area of triangle ABC)=6SQ UNITS
cruz:
Why you need to add area of triangle. If u subtract semicircle BD enough . This was my actual doubt
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hope this helps u :)))))))
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