Question

In the given figure triangle ABC is right angled at B and angle C=30°, find AC if AB=8cm.​

Answer 1

Answer:

sinC=AB/AC

sin 30°= 8/ AC

1/2=8/AC

AC= 16 cm

Answer 2

• Measure of AC is 16 cm.

Step-by-step explanation:

Given:-

• Angle B is right angle.
• Angle C of ∆ABC is 30°.
• AB of ∆ABC is 8 cm.

To find:-

• Measure of AC.

Solution:-

• By using trigonometric ratio's .That is :

$\sf \star \: sin \: 30\degree = \cfrac{1}{2}$--------(i)

$\sf \star \: sin \: \theta = \cfrac{Perpendicular}{Hypotenuse}$ --------(ii)

So,

By equation (i) and (ii)

$\longrightarrow \sf sin 30\degree = \cfrac{Perpendicular}{Hypotenuse}$

• Sin 30° = 1/2.

$\longrightarrow \sf \cfrac{1}{2} = \cfrac{AB}{AC}$

• AB = 8 cm.

$\longrightarrow \sf \cfrac{1}{2} = \cfrac{8}{AC}$

• Cross multiply

$\longrightarrow \sf AC = 8 \times 2$

$\longrightarrow \sf AC = 16$

Therefore,

AC is 16 cm.