In the given figure triangle ACB is a right angle triangle at C and CD AB If angle B :40 degree then find : Angle BAC , Angle ACD,Angle BCDplease help me fast
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given below
Step-by-step explanation:
in tri ACB, angle C=90 degree, angleB= 45 degree
SINCE THE SUM OF ALL ANGLES OF A TRIANGLE IS 180 DEGREE SO, ang.A PLUS ANG B PLUS ANG C=180 DEGREE
ANG. A
I WILL SOLVE THIS LATER FOR SURE . RIGHT NOW I HAVE SOME IMPORTANT WORK
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