Question

In the given figure triangle DEC is similar to triangle ABC. Area of ADEC = 25 cm² and area of ODEBA = 24 cm². If DE = 10cm, find the value of AB.

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Answer 1

Answer:

Step-by-step explanation:

if triangle abc is similar to triangle then AD/DC = BE/EC

therefore, DEllAB

and,

         area of triangle ABC/ are of triangle DEC =DE2 / AB2

Give that area of triangle DEC=25cm2

      therefore are of triangle ABC= area of DEC + area of ADBE

                                                       = 25 +24 = 49cm2

hence,

          49/25 = 100/AB2

     AB = root196 = 14cm

             

Answer 2

Step-by-step explanation:

If triangle abc is similar to triangle then

AD/DC = BE/EC

Therefore , DEllAB

and,area of triangle ABC/ are of triangle DEC =DE2 / AB2

Give that area of triangle DEC=25cm2

Therefore are of triangle ABC= area of DEC + area of ADBE = 25 +24 = 49cm2

hence,

        25/49 = 100/AB2

AB2 = 100/25 × 49

AB = √196

    AB = 14cm (Answer)