Question

in the given figure triangleABC is an isosceles triangle in which AB=AC and <A=50 Find measure of of <B and <C​

Answer 1

Answer :-

• The measure of ∠B = 65°
• The measure of ∠C = 65°

Step-by-step explanation:

To Find :-

• The measure of ∠B
• The measure of ∠C

Solution:

Given that,

• ∆ABC is an isosceles triangle
• ∠A = 50°

As we know that,

Vertex angle + two equal base angles = 180°

Assumption: Let assume the two equal angles ∠B and ∠C as "a" and "a"

Therefore,

• 50° + a + a = 180°

=> 50 + a + a = 180

=> 50 + 2a = 180

=> 2a = 180 - 50

=> 2a = 130

=> a = 130/2

=> a = 65

The value of x is 65. Now, The angles are :-

• The measure of ∠B

We assumed the measure of ∠B as "a"

=> a

=> 65°

• The measure of ∠C

We assumed the measure of ∠C as "a"

=> a

=> 65°

Hence, The measure of ∠B and ∠C are 65° and 65°.

Answer 2

Step-by-step explanation:

We know that triangle ABC is an isosceles .

We know that triangle ABC is an isosceles .In isosceles triangle two sides are equal and angle opposite to their equal side are also equal .

We know that triangle ABC is an isosceles .In isosceles triangle two sides are equal and angle opposite to their equal side are also equal .So, <B = <C (Take equatin :- 1 )

(Take equatin :- 1 )<A + <B+ <C = 180 ( sum of all angle of of triange 180 )

50 + <B + <B = 180 ( From equation 1 )

2 <B = 180 - 50

<B = 130 ÷ 2

<B = 65

Hence ;<B = <C = 65