Question

in the given figure two chords AB and CD intersect at E such that ∆ABC =50° and ∆AEC=120° find ∆CAE​

Answer 1

Explanation:

Given- O is the centre of a circle of which the chords AB and CD intersect at E.

∠BAC=45

o

and ∠BED=120

o

.

To find out- ∠ABD=?

Solution- ∠BAC=45

o

=∠BDC

Since both the angles are on the same chord BC ( the angles, subtended by a chord to different points of the circumference are equal).

So in ΔBDE, we have

∠EBD or ∠ABD=180

o

−(∠BED+∠BDE)=180

o

−(120

o

+45

o

)=15

o

.

Answer 2

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