in the given figure two line segment AC and BD intersect each other at point p such that pa=6cm pb=3cm pc=2.5cm pd=5cm APD =50 degree CPD=30 degree find the angle angle PBA
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In ΔABP and ΔCDP,
AP/BP = 6/3 = 2/1
DP/CP = 5/2.5 = 2/1
∠APB = ∠CPD
Hence they are proportional and similar.
So, ∠CDP = ∠PBA
∴ ∠PBA = 30°
AP/BP = 6/3 = 2/1
DP/CP = 5/2.5 = 2/1
∠APB = ∠CPD
Hence they are proportional and similar.
So, ∠CDP = ∠PBA
∴ ∠PBA = 30°
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