Question

in the given figure ,XY is the diameter of the circle,PQ is a tangent to the circle at Y.If angle ABX = 70 degree, calculate angle BAY and angle APY​

Answer 1

Answer:

<ABX = 70

<YXB = 50

<YXB = <BAY ( two intersecting chords always make equal corresponding angle with corresponding line or chord made by 2 chords)

Now,

In triangle XLB

<XLB = 180- <LXB - <XBL

= 180-50-70

= 60

<PLY = <XLB ( VERTICALLY OPP.ANGLE)

IN ∆LPY

<APY + LYP + <PLY = 180

AS XY IS TANGENT TO PQ

SO, XY BECOMES NORMAL

HENCE, <LYP = 90

SO, <APY + 90 + PLY = 180

<APY +90+60 = 180

<APY +150=180

<APY = 30

#answerwithquality #BAL

Answer 2

Answer:

ABX = 70

<YXB = 50

<YXB = <BAY ( two intersecting chords always make equal corresponding angle with corresponding line or chord made by 2 chords)

Now,

In triangle XLB

<XLB = 180- <LXB - <XBL

= 180-50-70

= 60

<PLY = <XLB ( VERTICALLY OPP.ANGLE)

IN ∆LPY

<APY + LYP + <PLY = 180

AS XY IS TANGENT TO PQ

SO, XY BECOMES NORMAL

HENCE, <LYP = 90

SO, <APY + 90 + PLY = 180

<APY +90+60 = 180

<APY +150=180

<APY = 30