In the given figure, ZADC = 130° and chord BC = chord BE. Find ZCBE.[NCERT C D 130% А 0 В E
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Class 9
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>>In the given figure, ADC = 130^∘ and ch
Question
In the given figure,∠ADC=130∘ and chord BC = chord BE. Find ∠CBE (in degrees)
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Solution
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Correct option is A)
In △BCO and △BEO
⇒ BC=BE [ Given ]
⇒ ∠BCO=∠BEO [ Base angles of equal sides are also equal ]
⇒ BO=BO [ Common side ]
∴ △BCO≅△BEO [ By SAS congruence rule ]
⇒ ∠CBO=∠OBE [ C.P.C.T. ]
Quadrilateral ABCD is a cyclic quadrilateral since, its points lies on a circle.
⇒ ∠ADC+∠CBA=180o [ Sum of opposite angles of a cyclic quadrilateral is supplementary ]
⇒ 130o+∠CBA=180o
⇒ ∠CBA=50o i.e. ∠CBO=50o
∴ ∠OBE=50o
⇒ ∠CBE=50o+50o=100o.
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