Question

In the given figures, perimeter of AXYZ = perimeter of parallelogram ABCD. Find AD.
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Answer 1

Answer:

Step-by-step explanation:

XYZ is right angled triangle so,

(XZ)² = (XY)² + (YZ)²

(13)² = (XY)² + (5)²

(XY)² = (13)²-(5)²

XY  =  $\sqrt{169-25}$

XY   =  $\sqrt{144}$

XY  =   12

it is given that perimeter of ΔXYZ = perimeter of ║ABCD

therefore,       XY+YZ+ZX = AB+BC+CD+AD

                         12+ 5+ 13  = 10+ BC+ 10+ AD

                                      30= 20+ 2(AD)................................( as AD = BC)

                               30-20 = 2(AD)

                                      10 = 2(AD)

                                     AD= 10/2

                                     AD= 5 cm