in the given isosceles triangle ABC AB is equal to BC if the measure of the exterior angle angle ebc is 100 degree find the measure of angle BCD and Angle A also find the base angles
nishkarshtak1234:
you must add the image of the diagram. in this type of question, a figure is always been given
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as per my assumption , ∠BCD will be 120° and ∠A will be 50°
plz solve
with full process
by linear pair , angle abc= 180-100=80. and because angle A and angle C are equal (bcoz AB=BC) thus 2xangle A + angleB =180. thus angleA and angleC = 50. again by linear pair axiom angle BCD+ angle BCA =180. therefore angle BCD =180-50= 130.
replace 120 by 130.
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