Question

In the given network, the equivalent resistance between A and B is

Answer 1

Answer:

Answer is A.

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Answer 2

Answer:

The equivalent resistance between A and B is R/2.

Explanation:

• PXQY form a balanced Wheatstone Bridge.
• So, there is no current flowing through the arm XY.
• The total resistances in upper arm of PQ is 2R and total resistance in the lower arm of PQ ia 2R.
• Equivalent resistance between P and Q is equal to parallel combination of 2R resistances.

$\frac{1}{R(pq)} = \frac{1}{2R} + \frac{1}{2R} \\ = \frac{1}{R} \\ R(pq) = R$

• Now, the equivalent resistance between A and B is equal to parallel combination of of R(pq) and R.

$\frac{1}{R(ab)} = \frac{1}{R} + \frac{1}{R} \\ = \frac{2}{R} \\ R(ab) = \frac{R}{2}$

• Hence, equivalent resistance between points A and B is R/2 .