Math, asked by munnarayeen06, 13 hours ago

in the given rectangle ABCD BP =BC what is the measurement of angle PCD?​

Answers

Answered by crevathy1969
20

Answer:

Step-by-step explanation:

ABCD is a rectangle

So all the angles are 90°

So,

Angle PBC = 90° and BCD = 90°

And Δ PBC is an isocels triangle

So angle BPC = BCP

Angle ( BPC + BCP + PBC ) = 180°

Angle ( BPC + BPC + PBC ) = 180°

Angle ( 2BPC + 90° ) = 180°

Angle ( 2BPC ) =180° -90°

Angle ( BPC ) = 90°/2

Angle BPC = 45°

So angle BCP = 45°

Angle PCD = 90° - Angle BCP

Angle PCD = 90°- 45°

Angle PCD = 45°

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